If the voltage in an AC transformer secondary contains twice as many loops as the primary, what happens to the voltage?

In an AC transformer, the relationship between the primary and secondary voltages is determined by the turns ratio, which is the ratio of the number of loops (turns) in the primary coil to the number of loops in the secondary coil. If the secondary coil contains twice as many turns as the primary, the voltage in the secondary will be greater than in the primary.

This increase in voltage occurs because of the principle of electromagnetic induction, where the voltage induced in the secondary coil is proportional to the number of turns in that coil compared to the primary. Specifically, the voltage in the secondary can be calculated using the formula:

[ V_s = V_p \times \left( \frac{N_s}{N_p} \right) ]

where ( V_s ) is the secondary voltage, ( V_p ) is the primary voltage, ( N_s ) is the number of turns in the secondary coil, and ( N_p ) is the number of turns in the primary coil. With the secondary having twice the number of turns, the voltage in the secondary will indeed be twice that of the primary voltage.

As the voltage increases, the current (amperage) in the secondary will decrease in accordance with the conservation