What happens to the amperage in an AC transformer if the secondary voltage is greater than the primary?

In an AC transformer, the relationship between the primary and secondary voltage and current is guided by the principle of conservation of energy, which states that power input equals power output, excluding losses. The power in an electrical system is defined as the product of voltage and current (P = V × I).

For an ideal transformer, the power in the primary side is equal to the power in the secondary side. This relationship can be expressed as ( V_p \times I_p = V_s \times I_s ), where ( V ) represents voltage, ( I ) represents current, and the subscripts ( p ) and ( s ) denote primary and secondary respectively.

If the secondary voltage is higher than the primary voltage, the voltage step-up in the transformer means the current in the secondary side (secondary amperage) will be lower compared to the primary side (primary amperage). This can be understood from the formula rearranged to express current: ( I_s = \frac{V_p}{V_s} \times I_p ). Since ( V_s > V_p ), it follows that ( I_s < I_p ).

Thus, when the secondary voltage is greater than the primary voltage, the amperage in the